36x^2-33x+6=0

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Solution for 36x^2-33x+6=0 equation: 



36x^2-33x+6=0

a = 36; b = -33; c = +6;
Δ = b2-4ac
Δ = -332-4·36·6
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-15}{2*36}=\frac{18}{72}
=1/4
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+15}{2*36}=\frac{48}{72}
=2/3
$

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